AP Calculus AB - Unit 6 Study Guide
6.1 - 6.2

Riemann Sums & Area Approximation

Before we can find exact area using integrals, we approximate it using rectangles (LRAM, RRAM, MRAM) or trapezoids.

Over vs. Under Estimate (Logic)

You don't need to draw it every time. Memorize the logic:

Function Behavior LRAM (Left) RRAM (Right)
Increasing (↗) Under Estimate Over Estimate
Decreasing (↘) Over Estimate Under Estimate

Note: Trapezoidal Sum depends on Concavity. Concave Up = Over; Concave Down = Under.

6.3

The Definite Integral

The Definite Integral is the limit of a Riemann Sum as the number of rectangles goes to infinity (n → ∞).

ab f(x) dx = limn→∞ Σ f(ci) Δx
Signed Area

Area above x-axis is Positive (+).

Area below x-axis is Negative (-).

Properties

aa f(x) dx = 0

ab = -∫ba

6.4

FTC Part 1: Accumulation Functions

This theorem establishes that Differentiation and Integration are inverse operations. It deals with functions defined by integrals.

The Theorem

If g(x) = ∫ax f(t) dt, then:

g'(x) = f(x)

"The derivative of the integral is the original function."

Chain Rule Alert: If the upper limit is not just x, but a function u(x):
d/dx ∫au f(t) dt = f(u) · u'
Example: d/dx ∫2 cos(t) dt = cos(x³) · 3x²
6.5

Analyzing Functions Defined by Integrals

The AP Exam loves to give you the graph of f(t) and ask you questions about g(x) = ∫ax f(t) dt. You must use FTC Part 1 to translate between them.

The "Translation" Key

Because g'(x) = f(x), the graph of f is actually the derivative graph of g.

  • If the graph of f is above the x-axis (f > 0), then g is increasing.
  • If the graph of f is below the x-axis (f < 0), then g is decreasing.
  • If the graph of f is increasing (f' > 0), then g is concave up.
  • If the graph of f is decreasing (f' < 0), then g is concave down.
6.6

Properties of Definite Integrals

You can manipulate integral limits and integrands using these algebraic properties.

Property Formula
Zero Width aa f(x) dx = 0
Reversing Limits ab f(x) dx = -∫ba f(x) dx (Flipping limits flips the sign!)
Additivity ab f(x) dx + ∫bc f(x) dx = ∫ac f(x) dx
Constant Multiple ∫ k·f(x) dx = k·∫ f(x) dx
6.7

FTC Part 2: Evaluation

This is how we actually calculate the value of a definite integral without using Riemann Sums.

The "Evaluation Bridge"

If F is the antiderivative of f (meaning F' = f), then:

ab f(x) dx = F(b) - F(a)

"End Value minus Start Value"

6.8

Indefinite Integrals & Antiderivatives

An indefinite integral ∫ f(x) dx asks for the general family of functions.

DON'T FORGET THE + C
If you write the antiderivative without + C, you will lose the point. Every time. No exceptions.
Rule Integral Formula
Reverse Power ∫ xⁿ dx = (xⁿ⁺¹)/(n+1) + C
1/x Rule ∫ (1/x) dx = ln|x| + C (Absolute value is crucial!)
Exponential ∫ eˣ dx = eˣ + C
Trig ∫ cos(x) dx = sin(x) + C
∫ sin(x) dx = -cos(x) + C
6.9

Integration by Substitution (U-Sub)

U-Sub is the "Reverse Chain Rule." It is used when you have a composite function inside the integral.

The U-Sub Algorithm

Problem: Evaluate 01 2x(x² + 1)³ dx

  1. Choose u: Let u = x² + 1 (the inside function).
  2. Differentiate: du = 2x dxdx = du / 2x.
  3. Change Limits:
    • If x = 0, u = 0² + 1 = 1.
    • If x = 1, u = 1² + 1 = 2.
  4. Substitute: 12 u³ du (The 2x cancels out).
  5. Integrate: [u⁴/4] from 1 to 2.
  6. Evaluate: (2⁴/4) - (1⁴/4) = 4 - 0.25 = 3.75.
Golden Rule of Definite U-Sub

Never return to x if you have changed your bounds to u. Just finish the problem in u-world. It's faster and less prone to error.

6.10

Algebraic Manipulation (Division & Completing the Square)

When basic integration and U-Substitution fail, we must alter the algebraic form of the integrand before integrating. These two algebra tricks are essential for AB Calculus.

Long Division

When to use: When the fraction is "Top-Heavy" (the degree of the numerator is $\ge$ the degree of the denominator).

How: Use polynomial long division to rewrite the improper fraction as a polynomial plus a proper fraction.

Example: ∫ (x² + x) / x dx = ∫ (x + 1) dx

Completing the Square

When to use: When the denominator is an irreducible quadratic (like $x^2 + 4x + 5$) and the numerator is a constant.

How: Force the denominator into the form (x+a)² + b², which perfectly sets up the arctan integration formula.

Example: 1/(x² + 2x + 2) → 1/((x+1)² + 1)

6.14

Selecting Techniques for Integration

When faced with a random integral on the exam, walk through this Decision Tree in your head to avoid getting stuck:

  1. Is it a basic rule? Look for simple power rules, 1/x, e^x, or basic trig functions. Expand or simplify first if needed.
  2. Can I use U-Substitution? Look for an "inside" function whose derivative is floating around on the "outside" (e.g., 2x outside of sin(x²)).
  3. Is it a Rational Function (Fractions)?
    • Is the numerator degree $\ge$ denominator degree? Use Long Division.
    • Is the denominator an unfactorable quadratic? Complete the Square (leads to arctan).
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